98p^2-2=0

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Solution for 98p^2-2=0 equation:



98p^2-2=0
a = 98; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·98·(-2)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28}{2*98}=\frac{-28}{196} =-1/7 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28}{2*98}=\frac{28}{196} =1/7 $

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